Free Length of Toytec/Eibach 3" coils??

[scrap metal]

What is the free length of Toytec/Eibach 3" Coils?

Reason I ask,
Currently have Tundra 5100s for my front shocks with tube bumper and winch. I am trying to decide between OME 883 coils and the Toytec/Eibach coils.

I'm confused because people on here say the 883 coils (590lbs) ride stiffer/harsher than the Eibach coils (620lbs). I always read the the eibach coils are smooth and not harsh, so I can only assume that the Eibach coils are a shorter free standing length than the OME 883????

SPECS:
OME 883: Length 375mm (14.74") @ 590 lbs.
Toytec Eibach: Length ???mm (?.??") @ 620 lbs.

Someone Enlighten me:thanks:

 

[the great him]

i would think that the eibach coils would be longer actually, being a heavier coild and a softer ride... and it seamed to me like my eibachs were more like 18" in length unsprung(free standing)

 

[scrap metal]

I was under the impression that compressing a longer coil into the 5100s would give it more preload and make it stiffer?? or is my logic just off.

Im just wondering why people say the 883s are more harsh even though they have a slightly lower rating

 

[kolelt]

I was under the impression that compressing a longer coil into the 5100s would give it more preload and make it stiffer?? or is my logic just off.

Im just wondering why people say the 883s are more harsh even though they have a slightly lower rating

People like the ride with 5100/eibachs. They say it's just perfect. Not to stiff not to soft.

 

[scrap metal]

Why are they smoother if theyre stiffer than the 883?

 

[Skidmarcx]

I was under the impression that compressing a longer coil into the 5100s would give it more preload and make it stiffer?? or is my logic just off.

Im just wondering why people say the 883s are more harsh even though they have a slightly lower rating

Those Eibachs are a linear spring it doesn't matter how much you preload it ... A 620lb/in linear spring will compress 1" per 620lbs... What WILL affect the ride is the weight distribution

 

[scrap metal]

My math and physics knowledge can't agree with your statement. A linear graph is y=x which means for every inch of compression the spring rate increases by the inches of compression. .. which means 2" compressed=620x2=1240lbs....????

 

[Skidmarcx]

My math and physics knowledge can't agree with your statement. A linear graph is y=x which means for every inch of compression the spring rate increases by the inches of compression. .. which means 2" compressed=620x2=1240lbs....????

You're correct it takes 1240lbs to compress a linear spring with the rate of 620lb/in a total of 2"