What's loads are you using out of curiosity?
The best way I can think of getting the amount of force would be to calculate the downward speed of the truck if it were to fall from a certain difference.
I would never jump my truck more than 3 ft and the rear suspension will be about 12" of travel so I'll use 4ft as an example.
Let's say my truck weighs about 4500lbs.
When my truck hits the ground something has to give, obviously the suspension will cushion the impact, however for this situation lets assume that the suspension is fully compressed at the bump stop and that only one tire impacts. The tire will compress a certain amount upon impact. Let's say 4"
To determine the force we use the old physics 1/2at² equation. First we need to find the speed of the truck.
x=x0+v0t+½at²
0=4+½(32.2)t² t=√(8/32.2)=1 seconds so thats 8 ft per second. well plug that into our second equation.
x=x0+Vav*T
0=1/3+(8+0)/2*T T=0.166
0=1/3+½a(0.166)² a=144*2/3=23ft/s²
the mass of my truck is 4500lb/32.2ft/s²=140slugs
so the force would be 140*76=3220lb+4500lb
so about 7,720*4/3= about 10,000lb and id like a safety factor of about 2 if possible. feel free to check my math and also change any of the numbers. another thing is that the force would be much less if you consider that the suspension compresses 9" and the bump stops and rubber bushings also compress as well. also if it hit only one tire it would flex while compressing adding even more travel to that.